NCERT Solutions for Class 9 Maths Chapter 12 — Exercise Set 12.4#
In any tiling, the angles of the tiles that meet around a point must add up to exactly 360° — no gaps and no overlaps.
1. Justify why the plane cannot be tiled with a regular pentagon. #
Solution
Each angle of a regular pentagon is:
$$\dfrac{(5 - 2) \times 180°}{5} = 108°$$Look at a corner of a tile. Around that point the angles must total 360°.
- If only pentagon corners meet there: $3 \times 108° = 324°$ leaves a gap of 36°, which no pentagon angle (108°) can fill; and $4 \times 108° = 432°$ is too much. Since $\dfrac{360}{108}$ is not a whole number, this is impossible.
- If the point lies on the side of another tile, that side contributes a straight angle of 180°, leaving 180° for pentagon corners: $108° = 108°$ leaves 72°, and $2 \times 108° = 216°$ is too much. Impossible again.
∴ Regular pentagons cannot meet around a point without gaps or overlaps, so they cannot tile the plane.
2. Draw a non-convex 4-gon DART. Show how we can tile the plane with copies of DART. Both methods that we discussed earlier will work. Which do you prefer? #
Method 1 : rotating about midpoints
- Draw DART (with the dent at $D$) and copy it.
- For each side, rotate a copy through 180° about the midpoint of that side. The rotated copy fits exactly along that side, because a half-turn about the midpoint swaps the two ends of the side.
- Repeat this at every side of every new copy.
Around each vertex, the four angles of DART (one from each of four copies) meet, and they add up to 360° — even with the reflex angle at $D$ — so the copies fit together with no gaps.
Method 2 : the Varignon grid
- Draw the Varignon parallelogram of DART (join the midpoints of its sides) and tile the plane with copies of this parallelogram, as a grid.
- Place a copy of DART on every other parallelogram of the grid (like the black squares of a chessboard), matching the way DART sits around its own Varignon parallelogram (Exercise Set 12.3, Q5).
- The gaps left over are also copies of DART — fill them in.
Which do you prefer?
Either answer is fine with a reason. Method 1 is easier to carry out with paper cut-outs (just keep turning copies about midpoints). Method 2 is easier to draw neatly, because the grid of parallelograms fixes where every copy goes.